Update merge_classes.py
完成:编写 265 类至 4 大类的数据集自动化合并脚本。
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1 changed files with 35 additions and 8 deletions
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@ -1,13 +1,30 @@
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"""将原数据集合并为我们需要的四个大类
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运行时先配置路径
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author:
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weikaiwen
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厨余垃圾-1
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可回收物-2
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其他垃圾-3
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有害垃圾-4
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未知-0
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"""
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import os
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import shutil
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# ================= 1. 配置你的路径 =================
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# 注意:请确保相对路径正确,以下为示例
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ORIGINAL_DATA_DIR = './garbage265' # 原始数据集的目录
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NEW_DATA_DIR = './garbage_4_classes' # 合并后的新目录
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CLASSNAME_FILE = './garbage265/classname.txt' # txt 文件的位置
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ORIGINAL_DATA_DIR = '/Users/weikaiwen/Desktop/trash_division_data' # 原始数据集的目录
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NEW_DATA_DIR = '/Users/weikaiwen/Desktop/trash_division_data/ultimate_4_class' # 合并后的新目录
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CLASSNAME_FILE = '/Users/weikaiwen/Desktop/trash_division_data/val/classname.txt' # txt 文件的位置
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# ===================================================
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def build_mapping():
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"""让 Python 自动读取 txt 文件并建立映射字典"""
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mapping = {}
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@ -24,14 +41,24 @@ def build_mapping():
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# 用 '-' 把字符串一分为二:前面的做大类,后面的做小类
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big_class, small_class = line.split('-', 1)
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# 核心:修复原数据集中的错别字 Bug
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# 修改错别字
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if big_class == '其它垃圾':
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big_class = '其他垃圾'
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# 为了绝对安全,我们把三种可能出现的文件夹名字全存进字典里:
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# 核心:变为数字分类
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if big_class == '厨余垃圾':
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big_class = '1'
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elif big_class == '可回收物':
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big_class = '2'
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elif big_class == '其他垃圾':
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big_class = '3'
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else :
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big_class = '4'
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# 把文件夹名字全存进字典里:
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mapping[str(idx)] = big_class # 应对文件夹名为数字 ID (如 '0') 的情况
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mapping[line] = big_class # 应对文件夹名为完整名称 (如 '厨余垃圾-八宝粥') 的情况
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mapping[small_class] = big_class # 应对文件夹名为小类名称 (如 '八宝粥') 的情况
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return mapping
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@ -59,7 +86,7 @@ def merge_dataset():
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continue
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# 核心:通过字典查询这个小类属于哪个大类
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target_big_class = class_mapping.get(sub_class, "未知分类")
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target_big_class = class_mapping.get(sub_class, "0")
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target_dir = os.path.join(new_split_dir, target_big_class)
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if not os.path.exists(target_dir):
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